2009-08-23
Notice the trailing zero before the 8. Heres how:
(DT_WSTR, 4) DATEPART( "yyyy", DATEADD( "dd" , -@DateCounter, GETDATE() ) )
+ "-" +
Right("0"+(DT_WSTR, 2)DATEPART( "mm", DATEADD( "dd" , -@DateCounter, GETDATE() ) ),2)
+"-"+
Right("0"+(DT_WSTR, 2)DATEPART( "dd", DATEADD( "dd" , -@DateCounter, GETDATE() ) ) ,2)
+" 00:00:00"
the hours mins and seconds are non dynamic in this case but I hope you get the drift.
The variable DateCounter will take you back as many days as you like.
A little more one how adding the zero worked:
- DT_WSTR,2 made the "mm" section return X8 where X is null.
- "0" + "X8" = "08" . But had it been say "11" then "0"+"11" = "011".
- Right (
,2) made "08" = "08 but had it been "011" as explained above it would be "11"
thanks very much buddy.....
ReplyDeletei nade it like
ReplyDelete@[User::Directory] + @[User::Filename]+" "+(DT_STR,4,1252)DATEPART( "yyyy" , getdate() ) +"-"+
RIGHT("0" + (DT_STR,4,1252)DATEPART( "mm" , getdate() ), 2) +"-"+
RIGHT("0" + (DT_STR,4,1252)DATEPART( "dd" , getdate() ), 2) +".csv"
But how can i findout yesterday's date????
????
Awesome! Thanks
ReplyDelete